State
How much solar do I need in Wyoming?
Wyoming averages 5.36 peak sun hours a day, so 1 kW of panels makes about 1,533 kWh a year. A home using 10 kWh a day needs about 2,488 W of panels.
| Daily use | Panel watts | 400 W panels | Battery for 1 day |
|---|---|---|---|
| 5 kWh/day | 1,244 W | 4 | 6.17 kWh |
| 10 kWh/day | 2,488 W | 7 | 12.35 kWh |
| 20 kWh/day | 4,975 W | 13 | 24.69 kWh |
| 30 kWh/day | 7,463 W | 19 | 37.04 kWh |
Peak sun hours: 5.36; annual output 1,533 kWh per kW. Source: state table derived from NREL PVWatts v8; check your exact address in NREL PVWatts.
Questions
How many peak sun hours does Wyoming get?
5.36 kWh/m²/day on average, from NREL PVWatts v8 data.
How many solar panels for a house in Wyoming?
Wyoming averages 5.36 peak sun hours a day, so 1 kW of panels makes about 1,533 kWh a year. A home using 10 kWh a day needs about 2,488 W of panels.